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4.16x^2-3.65x-1.48=0
a = 4.16; b = -3.65; c = -1.48;
Δ = b2-4ac
Δ = -3.652-4·4.16·(-1.48)
Δ = 37.9497
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.65)-\sqrt{37.9497}}{2*4.16}=\frac{3.65-\sqrt{37.9497}}{8.32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.65)+\sqrt{37.9497}}{2*4.16}=\frac{3.65+\sqrt{37.9497}}{8.32} $
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